# What is the differentiation of cosx sinx ?

## Solution :

Let y = cosx.sinx

By using product rule in differentiation,

$$dy\over dx$$ = sinx(-sinx) + cosx.cosx

$$dy\over dx$$ = $$cos^2x – sin^2x$$ = cos 2x

Hence, the differentiation of cosx.sinx with respect to x is cos 2x.

### Questions for Practice

What is the differentiation of $$e^{sinx}$$ ?

What is the differentiation of sin square x or $$sin^2x$$ ?

What is the differentiation of 1/sinx ?

What is the differentiation of $$sin x^2$$ ?

What is the differentiation of log sin x ?