What is the differentiation of cosx sinx ?

Solution :

Let y = cosx.sinx

By using product rule in differentiation,

\(dy\over dx\) = sinx(-sinx) + cosx.cosx

\(dy\over dx\) = \(cos^2x – sin^2x\) = cos 2x

Hence, the differentiation of cosx.sinx with respect to x is cos 2x.


Questions for Practice

What is the differentiation of \(e^{sinx}\) ?

What is the differentiation of sin square x or \(sin^2x\) ?

What is the differentiation of 1/sinx ?

What is the differentiation of \(sin x^2\) ?

What is the differentiation of log sin x ?

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