Solution :
We have, y = \(sin x^2\)
Differentiating with respect to x by using chain rule,
\(dy\over dx\) = \(cos x^2\).(2x)
\(dy\over dx\) = 2x.\(cos x^2\)
Hence, the differentiation of \(sin x^2\) with respect to x is 2x.\(cos x^2\)
Questions for Practice
What is the differentiation of \(e^{sinx}\) ?
What is the differentiation of sin square x or \(sin^2x\) ?
What is the differentiation of 1/sinx ?
