Solution :
We have, y = 1/sinx = cosecx
By using differentiation formula of cosecx,
\(dy\over dx\) = -cosecx.cotx
Hence, the differentiation of 1/sinx = -cosecx.cotx
Questions for Practice
What is the differentiation of \(e^{sinx}\) ?
What is the differentiation of sin square x or \(sin^2x\) ?
What is the differentiation of cosx sinx ?
