Area and Volume Questions

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 \(cm^3\) of wood has a mass of 0.6 g.

Solution : Inner Radius (r) = \(24\over 2\) = 12 cm Outer Radius (R) = \(28\over 2\) = 14 cm Height of Pipe = 35 cm Volume = \(\pi (R^2 – r^2) h\) = \(\pi \times 52 \times 35\) = 5720 \(cm^3\) Mass of 1 \(cm^3\) wood = 0.6 kg Mass of 5720 \(cm^3\) wood …

The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 \(cm^3\) of wood has a mass of 0.6 g. Read More »

If the lateral surface of a cylinder is 94.2 \(cm^2\) and its height is 5 cm, then find radius of its base and its volume.

Solution : Lateral or Curved Surface Area of Cylinder = \(2 \pi rh\) \(\implies\) \(2 \pi rh\) = 94.2 \(\implies\) \(2 \pi r \times 5\) = 94.2  \(\implies\) r = 3 cm Given, height = 5 cm Volume of Cylinder = \(\pi r^2 h\) = \(\pi \times 9 \times 5\) = \(3.14 \times 9 \times …

If the lateral surface of a cylinder is 94.2 \(cm^2\) and its height is 5 cm, then find radius of its base and its volume. Read More »

The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm.How many litres of water can it hold?

Solution : Circumference of the base cylindrical vessel = \(2\pi r\) \(\implies\)  \(2\pi r\) = 132    \(\implies\)  r = 21 cm Given, height = 25 cm Volume of cylinder = \(\pi r^2 h\) = \(\pi \times {21}^2 \times 25\) = 34650 \(cm^3\) Since 1litre = 1000 \(cm^3\) Therefore, It can hold 34.65 litres of …

The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm.How many litres of water can it hold? Read More »