The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 $$cm^3$$ of wood has a mass of 0.6 g.

Solution :

Inner Radius (r) = $$24\over 2$$ = 12 cm

Outer Radius (R) = $$28\over 2$$ = 14 cm

Height of Pipe = 35 cm

Volume = $$\pi (R^2 – r^2) h$$

= $$\pi \times 52 \times 35$$ = 5720 $$cm^3$$

Mass of 1 $$cm^3$$ wood = 0.6 kg

Mass of 5720 $$cm^3$$ wood = $$5720 \times 0.6$$ = 3432 g

Similar Questions

If the lateral surface of a cylinder is 94.2 $$cm^2$$ and its height is 5 cm, then find radius of its base and its volume.

The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm.How many litres of water can it hold?

What is the Formula for Volume of Cylinder ?

What is the Formula for Surface Area of Cylinder ?