The given parabola is of form \(y^2\) = 4ax. On comparing, we have 4a = 12 i.e a = 3.
We know that the focal distance of any point (x, y) on \(y^2\) = 4ax is x + a.
Let the given point on the parabola \(y^2\) = 12 x be (x, y). Then its focal distance be x + 3.
\(\therefore\) x + 3 = 4 \(\implies\) x = 1.
Hence, the abscissa of the given point is 1.