# The focal distance of a point on the parabola $$y^2$$ = 12x is 4. Find the abscissa of this point.

## Solution :

The given parabola is of form $$y^2$$ = 4ax. On comparing, we have 4a = 12 i.e a = 3.

We know that the focal distance of any point (x, y) on $$y^2$$ = 4ax is x + a.

Let the given point on the parabola $$y^2$$ = 12 x be (x, y). Then its focal distance be x + 3.

$$\therefore$$   x + 3 = 4 $$\implies$$  x = 1.

Hence, the abscissa of the given point is 1.

### Similar Questions

Find the value of k for which the point (k-1, k) lies inside the parabola $$y^2$$ = 4x.

The length of latus rectum of a parabola, whose focus is (2, 3) and directrix is the line x – 4y + 3 = 0 is

What is the equation of common tangent to the parabola $$y^2$$ = 4ax and $$x^2$$ = 4ay ?

What is the equation of tangent to the parabola having slope m?