# Find the value of k for which the point (k-1, k) lies inside the parabola $$y^2$$ = 4x.

## Solution :

$$\because$$ Point (k-1, k) lies inside the parabola $$y^2$$ = 4x.

$$\therefore$$  $${y_1}^2 – 4ax_1$$ < 0

$$\implies$$  $$k^2$$ – 4(k-1) < 0

$$\implies$$  $$k^2$$ – 4k + 4 < 0

$$(k-2)^2$$ < 0 $$\implies$$ k $$\in$$ $$\phi$$

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