# Find the inflection point of f(x) = $$3x^4 – 4x^3$$.

## Solution :

f(x) = $$3x^4 – 4x^3$$

f'(x) = $$12x^3 – 12x^2$$

f'(x) = $$12x^2(x – 1)$$

Now, f”(x) = $$12(3x^2 – 2x)$$

f”(x) = 12x(3x – 2)

f”(x) = 0  $$\implies$$  x = 0, 2/3

Here, f”(x) = 0

Thus, x = 0, 2/3 are the inflection points.

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