What is the Differentiation of log log x ?

Solution :

We have, y = log ( log x )

By using chain rule in differentiation,

$$dy\over dx$$ = $$1\over log x$$.$$1\over x$$

$$\implies$$ $$dy\over dx$$ = $$1\over x log x$$

Hence, the differentiation of log log x with respect to x is $$1\over x log x$$.

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