Solution :
We have, y = \(1\over log x\)
By using quotient rule in differentiation,
\(dy\over dx\) = \(log x.{d\over dx}(1) – 1 {d\over dx}(log x)\over (log x)^2\)
\(dy\over dx\) = \(0 – {1\over x}\over (log x)^2\) = \(-1\over x (log x)^2\)
Hence, the differentiation of 1/log x with respect to x is \(-1\over x (log x)^2\).
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