What is the Differentiation of x log x ?

Solution :

We have, y = x log x

By using product rule in differentiation,

\(dy\over dx\) = log x \(dy\over dx\)(x) + x \(dy\over dx\) (log x)

\(dy\over dx\) = log x + x/x

\(\implies\) \(dy\over dx\) = log x + 1

Hence, the differentiation of x log x with respect to x is log x + 1.


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