# What is the Differentiation of x log x ?

## Solution :

We have, y = x log x

By using product rule in differentiation,

$$dy\over dx$$ = log x $$dy\over dx$$(x) + x $$dy\over dx$$ (log x)

$$dy\over dx$$ = log x + x/x

$$\implies$$ $$dy\over dx$$ = log x + 1

Hence, the differentiation of x log x with respect to x is log x + 1.

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