Tick the correct answer and justify : In \(\triangle\), AB = \(6\sqrt{3}\) cm, AC = 12 cm and BC = 6 cm. The angle is : (i) 120 (ii) 60 (iii) 90 (iv) 45

Solution :

In triangle ABC, we have :triangle

AB = \(6\sqrt{3}\) cm , AC = 12 cm

and BC = 6 cm

Now, \({AB}^2\) + \({BC}^2\) = \((6\sqrt{3})^2\) + \((6)^2\)

= \(36 \times 3\) + 36 = 108 + 36 = 144 = \((AC)^2\)

Thus, triangle ABC is a right angled triangle at B.

\(\therefore\)  \(\angle\) B = 90

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