At a telephone enquiry system, the number of phone calls regarding relevant enquiry follow. Poisson distribution with an average of 5 phone calls during 10 min time intervals. The probability that there is almost one phone call during a 10 min time period is

Solution :

Required Probability = P(X = 0) + P(X = 1)

= $$e^{-5}\over 0!$$.$$5^0$$ + $$e^{-5}\over 1!$$.$$5^1$$

= $$e^{-5}$$ + 5$$e^{-5}$$ = $$6\over {e^5}$$

Similar Questions

The probability of India winning a test match against the west indies is 1/2 assuming independence from match to match. The probability that in a match series India’s second win occurs at the third test is

A fair die is tossed eight times. The probability that a third six is observed on the eight throw, is

If A and B are two mutually exclusive events, then

A and B play a game, where each is asked to select a number from 1 to 25. If the two numbers match, both of them win a prize. The probability that they will not win a prize in a single trial is

A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then, $$P(A \cup B)$$ is