Since variance is independent of change of origin.
Therefore, variance of observations 101, 102, …. , 200 is same as variance of 151, 152, ….. 250.
\(\therefore\) \(V_A\) = \(V_B\)
\(\implies\) \(V_A\over V_B\) = 1
The mean and variance of a random variable X having a binomial distribution are 4 and 2 respectively, then P(X = 1) is
The median of a set of 9 distinct observations is 20.5. If each of the largest 4 observation of the set is increased by 2, then the median of the new is
The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 success is
If the mean deviation about the median of numbers a, 2a, …. , 50a is 50, then |a| is equal to
The mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then, find the values of a and b?