## Solution :

A = {4. 5. 6} and B = {1, 2, 3, 4}

\(A \cap B\) = 4

\(\therefore\) \(P(A \cup B)\) = P(A) + P(B) – \(A \cap B\)

\(\implies\) \(P(A \cup B)\) = 3/6 + 4/6 – 1/6 = 1

A = {4. 5. 6} and B = {1, 2, 3, 4}

\(A \cap B\) = 4

\(\therefore\) \(P(A \cup B)\) = P(A) + P(B) – \(A \cap B\)

\(\implies\) \(P(A \cup B)\) = 3/6 + 4/6 – 1/6 = 1