# A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall.

## Solution :

Let ladder be AB, B be the window and CB be the wall. Then, ABC is a right triangle, angled at C.

$$\therefore$$  $${AB}^2$$ = $${AC}^2$$ + $${BC}^2$$

So,  $${10}^2$$ = $${AC}^2$$ + $$8^2$$

or  $${AC}^2$$ = 100 – 64

$$\implies$$ $${AC}^2$$ = 36

$$\implies$$  AC = 6 m