Given P(A) = 0.5, P(B) = 0.3 and P(C) = 0.2
\(\therefore\) P(A) + P(B) + P(C) = 1
then events A, B, C are exhaustive.
If P(E) = Probability of introducing a new product, then as given
P(E|A) = 0.7, P(E|B) = 0.6 and P(E|C) = 0.5
= 0.5 \(\times\) 0.7 + 0.3 \(\times\) 0.6 + 0.2 \(\times\) 0.5 = 0.35 + 0.18 + 0.10 = 0.63
The probability of India winning a test match against the west indies is 1/2 assuming independence from match to match. The probability that in a match series India’s second win occurs at the third test is
A bag contains 4 red and 4 blue balls. Four balls are drawn one by one from the bag, then find the probability that the drawn balls are in alternate color.
If A and B are two mutually exclusive events, then
A and B play a game, where each is asked to select a number from 1 to 25. If the two numbers match, both of them win a prize. The probability that they will not win a prize in a single trial is
A die is thrown. Let A be the event that the number obtained is greater than 3. Let B be the event that the number obtained is less than 5. Then, \(P(A \cup B)\) is