# The set A = [x : x $$\in$$ R, $$x^2$$ = 16 and 2x = 6] equal

## Solution :

$$x^2$$ = 16 $$\implies$$ x = $$\pm$$4

2x = 6 $$\implies$$ x = 3

There is no value of x which satisfies both the above equations.

Thus, A = $$\phi$$

### Similar Questions

If A = {x,y}, then the power set of A is

If aN = {ax : x $$\in$$ N}, then the set 6N $$\cap$$ 8N is equal to

Let A = [x: x $$\in$$ R, |x| < 1]; B = [x : x $$\in$$ R, |x – 1| $$\ge$$ 1] and A $$\cup$$ B = R – D, then the set D is

If A = {2, 4} and B = {3, 4, 5} then (A $$\cap$$ B) $$\times$$ (A $$\cup$$ B)

If N is a set of first 10 natural numbers and a relation R is defined as a + 2b = 10 where a, b $$\in$$ N. find inverse of R.