If N is a set of first 10 natural numbers and a relation R is defined as a + 2b = 10 where a, b \(\in\) N. find inverse of R.

Solution :

R = {(2, 4), (4, 3), (6, 2), (8, 1)}

\(R^{-1}\) = {(4, 2), (3, 4), (2, 6), (1, 8)}


Similar Questions

If A = {x,y}, then the power set of A is

If aN = {ax : x \(\in\) N}, then the set 6N \(\cap\) 8N is equal to

Let A = [x: x \(\in\) R, |x| < 1]; B = [x : x \(\in\) R, |x – 1| \(\ge\) 1] and A \(\cup\) B = R – D, then the set D is

The set A = [x : x \(\in\) R, \(x^2\) = 16 and 2x = 6] equal

Let A and B be two sets containing 2 elements and 4 elements, respectively. The number of subsets A\(\times\)B having 3 or more elements is

Leave a Comment

Your email address will not be published. Required fields are marked *