If N is a set of first 10 natural numbers and a relation R is defined as a + 2b = 10 where a, b \(\in\) N. find inverse of R.

Solution :

R = {(2, 4), (4, 3), (6, 2), (8, 1)}

\(R^{-1}\) = {(4, 2), (3, 4), (2, 6), (1, 8)}


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