# The number of ways of distributing 8 identical balls in 3 distinct boxes, so that none of the boxes is empty, is

## Solution :

The number of ways of distributing n identical things in m different boxes is $$^{n-1}C_{m-1}$$

So, Required number of ways = $$^{8-1}C_{3-1}$$

= $$^7C_2$$

= 21

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