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A student is to answer 10 out of 13 questions in an examination such that he must choose atleast 4 from the first five questions. The number of choices available to him is

Maths Questions, Permutation & Combination Questions / By mathemerize

Solution :

The number of choices available to him

= \(^5C_4\) x \(^8C_6\) + \(^5C_5\) x\(^8C_5\)

= 5.4.7 + 8.7

= 140 + 56

= 196


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