# In figures, (i) and (ii) DE || BC. Find EC in (i) and AD in (ii).

## Solution :

(i)  In figure (i)

Since DE || BC, therefore

$$AD\over DB$$ = $$AE\over EC$$

$$\implies$$  $$1.5\over 3$$ = $$1\over EC$$

$$\implies$$  EC = 2 cm.

(ii)  In figure (ii),

Since DE || BC, therefore

$$AD\over DB$$ = $$AE\over EC$$

$$\implies$$  $$AD\over 7.2$$ = $$1.8\over 5.4$$

$$\implies$$  AD = 2.4 cm.