Solution :
Since PS is the median, so S is the mid point of triangle PQR.
So, Coordinates of S = (\({7+6\over 2}, {3 – 1\over 2}\)) = (\(13\over 2\), 1)
Slope of line PS = (1 – 2)/(13/2 – 2) = \(-2\over 9\)
Required equation passes through (1, -1) is
y + 1 = \(-2\over 9\)(x – 1)
\(\implies\) 2x + 9y + 7 = 0
Similar Questions
Find the distance between the line 12x – 5y + 9 = 0 and the point (2,1)
If the line 2x + y = k passes through the point which divides the line segment joining the points (1,1) and (2,4) in the ratio 3:2, then k is equal to
The x-coordinate of the incenter of the triangle that has the coordinates of mid-point of its sides as (0,1), (1,1) and (1,0) is
Let a, b, c and d be non-zero numbers. If the point of intersection of the lines 4ax+2ay+c=0 and 5bx+2by+d=0 lies in the fourth quadrant and is equidistant from the two axes, then
If p is the length of the perpendicular from the origin to the line \(x\over a\) + \(y\over b\) = 1, then prove that \(1\over p^2\) = \(1\over a^2\) + \(1\over b^2\)
