If PS is the median of the triangle, with vertices of P(2,2), Q(6,-1) and R(7,3), then equation of the line passing through (1,-1) and parallel to PS is

Solution :

Since PS is the median, so S is the mid point of triangle PQR.

So, Coordinates of S = (\({7+6\over 2}, {3 – 1\over 2}\)) = (\(13\over 2\), 1)

Slope of line PS = (1 – 2)/(13/2 – 2) = \(-2\over 9\)

Required equation passes through (1, -1) is

y + 1 = \(-2\over 9\)(x – 1)

\(\implies\) 2x + 9y + 7 = 0


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