# Find the distance between the line 12x – 5y + 9 = 0 and the point (2,1)

## Solution :

We have line 12x – 5y + 9 = 0 and the point (2,1)

Required distance = |$$12*2 – 5*1 + 9\over {\sqrt{12^2 + (-5)^2}}$$|

= $$|24-5+9|\over 13$$ = $$28\over 13$$

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