Find the coordinates of the point of intersecton of the lines 2x – y + 3 = 0 and x + y – 5 = 0.

Solution :

Solving simultaneously the equations 2x – y + 3 = 0 and x + y – 5 = 0, we obtain

\(x\over {5 – 3}\) = \(y\over {3 + 10}\) = \(1\over {2 + 1}\)

\(\implies\) \(x\over 2\) = \(y\over 13\) = \(1\over 3\)

\(\implies\) x = \(2\over 3\) , y = \(13\over 3\)

Hence, (2/3, 13/3) is the required point of intersection.


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