Since, Slope of line passing through two points is m = \(y_2 – y_1\over x_2 – x_1\).
so, slope of chord passing through two points is \(4-(-3)\over 3-2\) = 7
Now, Tangent line is parallel to chord. Therefore slope of tangent line is equal to slope of chord,
Hence slope of tangent line is also 7.
If the straight line 3x + 4y + 5 – k(x + y + 3) = 0 is parallel to y-axis, then the value of k is
If the line 2x + y = k passes through the point which divides the line segment joining the points (1,1) and (2,4) in the ratio 3:2, then k is equal to
If x + 4y – 5 = 0 and 4x + ky + 7 = 0 are two perpendicular lines then k is
Find the equation of lines which passes through the point (3,4) and the sum of intercepts on the axes is 14.
If p is the length of the perpendicular from the origin to the line \(x\over a\) + \(y\over b\) = 1, then prove that \(1\over p^2\) = \(1\over a^2\) + \(1\over b^2\)