A problem in mathematics is given to three students A, B, C and their respective probability of solving the problem is \(1\over 2\), \(1\over 3\) and \(1\over 4\). Probability that the problem is solved is

Solution :

Since the probability of solving the problem by A, B and C is \(1\over 2\), \(1\over 3\) and \(1\over 4\) respectively.

\(\therefore\)  Probability that problem is not solved is

= P(A’)P(B’)P(C’)

= (\(1 – {1\over 2}\))(\(1 – {1\over 3}\))(\(1 – {1\over 4}\))

= \(1\over 2\)\(2\over 3\)\(3\over 4\) = \(1\over 4\)

= Hence, the probability that the problem is solved

= \(1 – {1\over 4}\) = \(3\over 4\)

Similar Questions

The probability of India winning a test match against the west indies is 1/2 assuming independence from match to match. The probability that in a match series India’s second win occurs at the third test is

A fair die is tossed eight times. The probability that a third six is observed on the eight throw, is

If A and B are two mutually exclusive events, then

A and B play a game, where each is asked to select a number from 1 to 25. If the two numbers match, both of them win a prize. The probability that they will not win a prize in a single trial is

At a telephone enquiry system, the number of phone calls regarding relevant enquiry follow. Poisson distribution with an average of 5 phone calls during 10 min time intervals. The probability that there is almost one phone call during a 10 min time period is

Leave a Comment

Your email address will not be published. Required fields are marked *