# A pair of fair dice is thrown independently three times. The probability of getting a score of exactly 9 twice is

## Solution :

Probability of getting score 9 in a single throw

= $$4\over 36$$ = $$1\over 9$$

Probability of getting score 9 exactly in double throw

= $$^3C_2$$ $$\times$$ $$({1\over 9})^2$$ $$\times$$ $$8\over 9$$ = $$8\over 243$$

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