What is the integration of 1/x log x ?

Solution :

We have, I = \(\int\) \(1\over x log x\) dx

Put log x = t \(\implies\) \(1\over x\) dx = dt

I = \(\int\)  \(1\over t\) dt

I = log | t | + C

I = log |log x| + C

Hence, the integration of \(1\over x log x\) is log (log x) + C


Similar Questions

What is the integration of log cos x dx ?

What is the integration of log 1/x ?

What is the integration of \((log x)^2\) dx ?

What is the integration of x log x dx ?

Leave a Comment

Your email address will not be published.