## Solution :

If out of n points, m are collinear, then

Number of triangles = \(^nC_3\) – \(^mC_3\)

\(\therefore\) Number of triangles = \(^{10}C_3\) – \(^6C_3\)

= 120 – 20

= 100

If out of n points, m are collinear, then

Number of triangles = \(^nC_3\) – \(^mC_3\)

\(\therefore\) Number of triangles = \(^{10}C_3\) – \(^6C_3\)

= 120 – 20

= 100