Solution :
The given parabola is of form y2 = 4ax. On comparing, we have 4a = 12 i.e a = 3.
We know that the focal distance of any point (x, y) on y2 = 4ax is x + a.
Let the given point on the parabola y2 = 12 x be (x, y). Then its focal distance be x + 3.
∴ x + 3 = 4 ⟹ x = 1.
Hence, the abscissa of the given point is 1.
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