# Prove that Empty Set is a Subset of Every Set.

## Solution :

Let A be any set and $$\phi$$ be the empty set.

In order to show that $$\phi$$ $$\subseteq$$ A, we must show that every element of $$\phi$$ is an element of A also. But, $$\phi$$ contains no element.

So, every element of $$\phi$$ is in A.

Hence, $$\phi$$ is the subset of A.