## Find the inflection point of f(x) = $$3x^4 – 4x^3$$.

Solution : f(x) = $$3x^4 – 4x^3$$ f'(x) = $$12x^3 – 12x^2$$ f'(x) = $$12x^2(x – 1)$$ Now, f”(x) = $$12(3x^2 – 2x)$$ f”(x) = 12x(3x – 2) f”(x) = 0  $$\implies$$  x = 0, 2/3 Here, f”(x) = 0 Thus, x = 0, 2/3 are the inflection points. Similar Questions Prove that the function …