Solution :
Given, sec 4A = cosec(A – 20)
\(\implies\) cosec(90 – 4A) = cosec(A – 20)
\(\implies\) 90 – 4A = A – 20
\(\implies\) 5A = 110
\(\implies\) A = 22
Given, sec 4A = cosec(A – 20)
\(\implies\) cosec(90 – 4A) = cosec(A – 20)
\(\implies\) 90 – 4A = A – 20
\(\implies\) 5A = 110
\(\implies\) A = 22