# Find the middle term in the expansion of $$({2\over 3}x^2 – {3\over 2x})^{20}$$.

## Solution :

Here, n = 20, which is an even number.

So, $${20\over 2} + 1$$th term i.e. 11th term is the middle term.

Hence, the middle term = $$T_{11}$$

$$T_{11}$$ = $$T_{10 + 1}$$ = $$^{20}C_{10}$$ $$({2\over 3}x^2)^{20 – 10}$$ $$(-{3\over 2x})^{10}$$

= $$^{20}C_{10} x^{10}$$

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