# Find dot product of vectors $$\vec{a}$$ = $$2\hat{i}+2\hat{j}-\hat{k}$$ and $$\vec{b}$$ = $$6\hat{i}-3\hat{j}+2\hat{k}$$

## Solution :

We have $$\vec{a}$$ = $$2\hat{i}+2\hat{j}-\hat{k}$$ and $$\vec{b}$$ = $$6\hat{i}-3\hat{j}+2\hat{k}$$

$$\vec{a}$$.$$\vec{b}$$ = ($$2\hat{i}+2\hat{j}-\hat{k}$$).($$6\hat{i}-3\hat{j}+2\hat{k}$$)

= (2)(6) + (2)(-3) + (-1)(2) = 12 – 6 – 2 = 4

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