Given Pair of linear equations are :
x – y + 1 = 0 ……(i)
and 3x + 2y – 12 = 0 …….(ii)
first we find points for equation (i),
|y = x + 1||1||5|
second we find points for equation (ii),
|y = \(12 – 3x\over 2\)||6||0|
Now, plot the points A(0,1), B(4, 5) and join them to get AB.
Similarly, plot the points in second table i.e. points C, E and join them to form a line CE.
Clearly, the two lines AB and CE intersect each other at the point D(2, 3).
Hence, the solution of the given pair of linear equations is x = 2 and y = 3.
Hence, the triangle formed is having vertices with the coordinates : D(2, 3), E(4, 0), F(-1, 0).