Here, you will learn Different Types of Parabola and Standard equations of parabola, focal chord, double ordinate and latus rectum of parabola.
Let’s begin –
What is Parabola ?
A parabola is the locus of a point which moves in a plane, such that its distance from a fixed point(focus) is equal to its perpendicular distance from a fixed straight line(directrix).
The Standard equation of parabola is y2=4ax and it is shown in figure. For this parabola :
(i) Vertex is (0,0).
(ii) focus is (a,0)
(iii) Axis is y = 0
(iv) Directrix is x + a = 0
(a) Focal distance :
The distance of a point on the parabola from the focus is called the focal distance of the point.
(b) Focal chord :
A chord of the parabola, which passes through the focus is called a focal chord.
(c) Double ordinate :
A chord of the parabola perpendicular to the axis of the symmetry is called double ordinate.
(d) Latus rectum :
A double ordinate passing through the focus or a focal chord perpendicular to the axis of parabola is called latus rectum.
For y2=4ax.
Length of the latus rectum = 4a
Length of the semi latus rectum = 2a
Ends of the latus rectum are L(a, 2a) & L'(a, -2a).
Note :
(i) Perpendicular distance from focus on the directrix = half the latus rectum.
(ii) Vertex is middle point of the focus & point of intersection of directrix & axis.
(iii) Two parabolas are said to be equal if they have the same latus rectum.
Different Types of Parabola & Standard Equations of Parabola
Four different types of parabola equations are
y2 = 4ax ; y2 = -4ax ; x2 = 4ay ; x2 = -4ay.
One I had shown above and three others are shown below.

y2 = -4ax

x2 = 4ay

x2 = -4ay
Parabola | Vertex | Focus | Axis | Directrix |
---|---|---|---|---|
y2 = 4ax | (0,0) | (a,0) | y = 0 | x = -a |
y2 = -4ax | (0,0) | (-a,0) | y = 0 | x = a |
x2 = +4ay | (0,0) | (0,a) | x = 0 | y = -a |
x2 = -4ay | (0,0) | (0,-a) | x = 0 | y = a |
(y−k)2 = 4a(x-h) | (h,k) | (h+a,k) | y = k | x+a-h = 0 |
(x−p)2 = 4b(y-q) | (p,q) | (p,b+q) | x = p | y+b-q = 0 |
Length of Latus rectum | Ends of Latus rectum | Parametric equation | Focal length |
---|---|---|---|
4a | (a,±2a) | (at2, 2at) | x + a |
4a | (-a,±2a) | (-at2, 2at) | x – a |
4a | (±2a,a) | (2at, at2) | y + a |
4a | (±2a,-a) | (2at, -at2) | y – a |
4a | (h+a, k±2a) | (h+at2, k+2at) | x – h + a |
4b | (p±2a, q+a) | (p+2at, q+at2) | y – q + b |
Example : Find the vertex, axis, directrix, focus, latus rectum and the tangent at vertex for the parabola 9y2–16x–12y–57 = 0.
Solution : The given equation can be written as (y−23)2 =
169(x+6116) which is of the form y2 = 4ax. Hence the vertex is (-6116, 23)
The axis is y – 23 = 0 ⟹ y = 23
The directrix is x + a – h = 0 ⟹ x + 6116 + 49 ⟹ x = −613144
The focus is (h+a, k) ⟹ (−485144, 23)
Length of the latus rectum = 4a = 169
The tangent at the vertex is x – h = 0 ⟹ x = −6116
Position of a point relative to a parabola :
The point (x1,y1) lies outside, on or inside the parabola y2 = 4ax1 is positive, zero or negative.
Related Questions
Find the value of k for which the point (k-1, k) lies inside the parabola y2 = 4x.
The focal distance of a point on the parabola y2 = 12x is 4. Find the abscissa of this point.
The slope of the line touching both the parabolas y2 = 4x and x2 = -32 is