# Angle between asymptotes of hyperbola xy=8 is

## Solution :

Since given hyperbola xy = 8 is rectangular hyperbola.

And eccentricity of rectangular hyperbola is $$\sqrt{2}$$

Angle between asymptotes of hyperbola is $$2sec^{-1}(e)$$

$$\implies$$ $$\theta$$ = $$2sec^{-1}(\sqrt{2})$$

$$\implies$$ $$\theta$$ = $$2sec^{-1}(sec 45)$$

$$\implies$$ $$\theta$$ = 2(45) = 90

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