A random variable X has poisson distribution with mean 2. Then, P(X > 1.5) equal to

Solution :

Now, P(X > 1.5) = P(2) + P(3) + …… \(\infty\)

= 1 – [P(0) + P(1)]

= 1 – \((e^{-2} + {e^{-2}(2)\over 1})\) = 1 – \(3\over e^2\)


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