What is the Differentiation of log log x ?

Solution :

We have, y = log ( log x )

By using chain rule in differentiation,

$dy\over dx$ = $1\over log x$.$1\over x$

$\implies$ $dy\over dx$ = $1\over x log x$

Hence, the differentiation of log log x with respect to x is $1\over x log x$.

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