Solution :
We have, y = log ( log x )
By using chain rule in differentiation,
\(dy\over dx\) = \(1\over log x\).\(1\over x\)
\(\implies\) \(dy\over dx\) = \(1\over x log x\)
Hence, the differentiation of log log x with respect to x is \(1\over x log x\).
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