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Let A and B be two sets containing 2 elements and 4 elements, respectively. The number of subsets A×B having 3 or more elements is

Solution :

Given, n(A) = 2 and n(B) = 4

n(A×B) = 8

The number of subsets of (AtimesB) having 3 or more elements = 8C3+8C4+..+8C8

= 288C08C18C2

= 256 – 1 – 8 – 28 = 219     [ 2n = nC0+nC1+..+nCn]


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