Solution :
Given, n(A) = 2 and n(B) = 4
∴ n(A×B) = 8
The number of subsets of (AtimesB) having 3 or more elements = 8C3+8C4+…..+8C8
= 28–8C0–8C1–8C2
= 256 – 1 – 8 – 28 = 219 [∵ 2n = nC0+nC1+…..+nCn]
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