Prove that \(sin^2 \theta\) + \(cos^2 \theta\) = 1.
Solution : In right angled triangle ABC, \(sin \theta\) = \(BC\over AC\) \(\implies\) \(sin^2 \theta\) = \(BC^2\over AC^2\) \(cos \theta\) = \(AB\over AC\) \(\implies\) \(cos^2 \theta\) = \(AB^2\over AC^2\) On adding, \(sin^2 \theta\) + \(cos^2 \theta\) = \(BC^2\over AC^2\) + \(AB^2\over AC^2\) \(sin^2 \theta\) + \(cos^2 \theta\) = \(BC^2 + AB^2\over AC^2\) = \(AC^2\over AC^2\) […]
Prove that \(sin^2 \theta\) + \(cos^2 \theta\) = 1. Read More »