Solution :
The value of sin 0 degrees is equal to 0.
Proof :
\(\angle\) A is made smaller and smaller in the right \(\Delta\) ABC till it becomes zero. As \(\angle\) A gets smaller and smaller the length of the side BC decreases. The point C gets closer to the point B and finally when \(\angle\) A becomes very close to 0 degrees, AC becomes almost the same as AB, and BC gets very close to 0.
By using trigonometric formula,
sin A = \(perpendicular\over base\) = \(p\over b\)
sin A = \(BC\over AB\) = \(0\over AC\) = 0
Hence, \(sin 0^{\circ}\) = 0