Solution :
The value of sin 0 degrees is equal to 0.
Proof :
∠ A is made smaller and smaller in the right Δ ABC till it becomes zero. As ∠ A gets smaller and smaller the length of the side BC decreases. The point C gets closer to the point B and finally when ∠ A becomes very close to 0 degrees, AC becomes almost the same as AB, and BC gets very close to 0.
By using trigonometric formula,
sin A = perpendicularbase = pb
sin A = BCAB = 0AC = 0
Hence, sin0∘ = 0