# What is integration of sin inverse cos x ?

## Solution :

We have, I = $$\int$$ $$sin^{-1}(cos x)$$ dx

By using integration formula, cos x = $$sin({\pi\over 2} – x)$$

I = $$\int$$ $$sin^{-1}[sin({\pi\over 2} – x)]$$ dx

I = $$\int$$ $$({\pi\over 2} – x)$$ dx

I = $${\pi\over 2}x$$ – $$x^2\over 2$$ + C

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