The slope of tangent parallel to the chord joining the points (2, -3) and (3, 4) is

Solution :

Since, Slope of line passing through two points is m = \(y_2 – y_1\over x_2 – x_1\).

so, slope of chord passing through two points is \(4-(-3)\over 3-2\) = 7

Now, Tangent line is parallel to chord. Therefore slope of tangent line is equal to slope of chord,

Hence slope of tangent line is also 7.

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