The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 \(cm^3\) of wood has a mass of 0.6 g.

Solution :

Inner Radius (r) = \(24\over 2\) = 12 cm

Outer Radius (R) = \(28\over 2\) = 14 cm

Height of Pipe = 35 cm

Volume = \(\pi (R^2 – r^2) h\)

= \(\pi \times 52 \times 35\) = 5720 \(cm^3\)

Mass of 1 \(cm^3\) wood = 0.6 kg

Mass of 5720 \(cm^3\) wood = \(5720 \times 0.6\) = 3432 g