Solution :
S = { 00, 01, 02, ……, 49 }
Let A be the event that sum of the digits on the selected ticket is 8, then
A = { 08, 17, 26, 35, 44 }
Let B be the event that the product of the digits is zero.
B = { 00, 01, 02, 03, …. , 09, 10, 20, 30, 40 }
\(\therefore\) \(A \cap B\) = { 8 }
\(\therefore\) Required probability = \(P({A\over B})\) = \(P(A \cap B)\over P(B)\)
= \(1/50\over 14/50\) = \(1\over 14\)
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