Discuss the continuity and differentiability of the function y = f(x) defined parametrically; x = 2t – |t-1| and y = 2\(t^2\) + t|t|.
Solution : Here x = 2t – |t-1| and y = 2\(t^2\) + t|t|. Now when t < 0; x = 2t – {-(t-1)} = 3t – 1 and y = 2\(t^2\) – \(t^2\) = \(t^2\) \(\implies\) = y = \({1\over 9}{(x+1)}^2\) = when 0 \(\le\) t < 1 x = 2t – {-(t-1)} = […]