Find \(dy\over dx\) where x = a{cos t + \({1\over 2} log tan^2 {t\over 2}\)} and y = a sin t
Solution : We have, x = a{cos t + \({1\over 2} log tan^2 {t\over 2}\)} and y = a sin t \(\implies\) x = a{cos t + \({1\over 2} \times 2 log tan{t\over 2}\)} and y = a sin t \(\implies\) x = a{cos t + {\(log tan{t\over 2}\)} and y = a sin t […]